10 123... — 7.6 /

: If letter is an empty string, the loop would run forever; we return the original word immediately.

def remove_all_from_string(word, letter): # If the letter to remove is empty, return the original word if letter == "": return word while True: # Find the first occurrence of the letter index = word.find(letter) # If .find() returns -1, the letter is no longer in the string if index == -1: return word # Rebuild the string by skipping the found instance word = word[:index] + word[index + len(letter):] # Example usage: # word = input("Enter word: ") # letter = input("Enter letter to remove: ") # print(remove_all_from_string(word, letter)) Use code with caution. Copied to clipboard Breakdown of the Code 7.6 / 10 123...

While the CodeHS exercise often requires the manual loop approach above, the simplest way to do this in standard Python is using the .replace() method: : If letter is an empty string, the

def remove_all_from_string(word, letter): return word.replace(letter, "") Use code with caution. Copied to clipboard Copied to clipboard The prompt likely refers to

The prompt likely refers to from the CodeHS Python curriculum. This exercise requires you to write a function that removes every instance of a specific "letter" (or substring) from a given word. Correct Python Implementation